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2x2+54=42得多少

(2x+x)X2=54 (2x+1x)x2÷2=54÷2 3x =27 3x÷3=27÷3 x=9

2【X+(54-2X)%(除号)2】=54(两边÷2) [x+(54-2x)/100÷2]=27 [x+(54-2x)/100*1/2]=27 x+(54-2x)/200=27(通分) 200x+54-2x=5400 198x=5346 x=27

去括号 144-X=2*54+2X 移项,合并同类项 144-108=3x 3x=36 将系数化成1 x=12

54一7.2x=25.2 解:7.2x=54-25.2 7.2x=28.8 x=28.8÷7.2 x=4

2x+4(20-x)=54 2x+80-4x =54 2x = 80-54 x = 13

2x20x+5x=54 40x+5x=54 45x=54 x=1.2

显然a≠0由△=16a2-16a(a+4)≥0得a<0,由韦达定理知x1+x2=1,x1x2=a+44a,所以(x1?2x2)(x2?2x1)=5x1x2?2(x21+x22)=9x1x2?2(x1+x2)2=9(a+4)4a?2=a+364a若有(x1?2x2)(x2?2x1)=54,则a+364a=54,∴a=9,这与a<0矛盾,故不存在a,使(x1?2x2)?...

6.8×2-2x=54 13.6-2x=54 2x=13.6-54 2x=-40.4 x=-20.2

2x=16 x=16÷2 x=8 x减1.9=2 x=2+1.9 x=3.9 2x+3=17 2x=17-3 2x=14 x=14÷2 x=7 4x减2x=54 2x=54 x=54÷2 x=27

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